4ln(x)+3y^2=1

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Solution for 4ln(x)+3y^2=1 equation: 


Simplifying
4ln(x) + 3y2 = 1

Multiply ln * x
4lnx + 3y2 = 1

Solving
4lnx + 3y2 = 1

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-3y2' to each side of the equation.
4lnx + 3y2 + -3y2 = 1 + -3y2

Combine like terms: 3y2 + -3y2 = 0
4lnx + 0 = 1 + -3y2
4lnx = 1 + -3y2

Divide each side by '4nx'.
l = 0.25n-1x-1 + -0.75n-1x-1y2

Simplifying
l = 0.25n-1x-1 + -0.75n-1x-1y2

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